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From a point A on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, the distance of point A from the foot of the tower is:
Answer is 173 m
sin30 = 100 / hyp side
hyp side = 200
Now for distance of point A from the foot of the tower =cos30 * hyp side = 0.866 * 200 = 173 m
Distance from A to bottom of tower=P
Height of tower =100m
Angle of elevation from point A=30°
Therefore Tan 30°=100/P
So ans is 173m
From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, Then what is the the distance of point P from the foot of the tower.
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