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From a point A on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, the distance of point A from the foot of the tower is:

Answer is 173 m sin30 = 100 / hyp side

hyp side = 200 Now for distance of point A from the foot of the tower =cos30 * hyp side = 0.866 * 200 = 173 m

Distance from A to bottom of tower=P Height of tower =100m Angle of elevation from point A=30° Therefore Tan 30°=100/P P=100/tan30° =100/(1/√3) =173 So ans is 173m

From a point P on a level ground, the angle of elevation of the top tower is 30º. If the tower is 100 m high, Then what is the the distance of point P from the foot of the tower.

At a particular time the shadow of a men of 170 cm height is 204 cm on the ground and at the same time and on the same ground the shadow of a pole is 600 cm. Find the height of the pole?

Two poles of height 12 m. and 4 m. are situated in such a way that the sun rays through the top of a pole also passes through the top of other. What is the distance between the poles? It is given that the sun rays make an angle of 45 degree with the horizon

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A boy 1.4 m tall casts a shadow 1.2 m long at the time when building casts a shadow 5.4 m long. What is the height of the building.