If (3!)^2 - (2!)^1 - (1!)^0 - 3! - 2! - 1! - 0! = 7 + x^2 then x^2 - 3x/2

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If
(3!)^2 - (2!)^1 - (1!)^0 - 3! - 2! - 1! - 0! = 7 + x^2
then
x^2 - 3x/2 - 4 = ?

posted Feb 22, 2017 by anonymous
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2 Answers (Check Answer ▼)

6 or 18 Explanation as under
36-2-1-6-2-1-1=7+x^2 or x^2=16 leaving x to be +/- 4
for x^2- 1.5x-4 with x=4 the answer is 16-6-4=6
with x=-4 the answer is 16+6-4=18

answer Feb 22, 2017 by Kewal Panesar

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If (3!)^2 - (2!)^1 - (1!)^0 - 3! - 2! - 1! - 0! = 7 + x^2 then x^2 - 3x/2 - 4 = ?

2 Answers (Check Answer ▼)

Your answer

Preview