Find a two-digit number so that when the digits are added together the answer is one half of the answer you get when the 2 digits are multiplied together.
44, 4*4=2(4+4)
Using the digits 1, 2, 3 and 4, find the number of 10-digit sequences that can be written so that the difference between any two consecutive digits is 1.
Examples of such 10-digit sequences are ********** and **********.
Given the number 123456789. Find a permutation of the number's digits such, that the left most digit is evenly divisible by 1, the two left most digits are evenly divisible by 2, the three left most digits are divisibly by 3 and so on?
I am thinking of a five digit number such that: First and last digits are same, their submission is an even number and multiplication is an odd number and is equal to the fourth number. Subtract five from it and we obtain the second number. Then divide into exact half nd we get 3rd number.
What number I am thinking of?
