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9^(3-x) = 81^(4-2x) => 9^(3-x) = 9^(8-4x) => 3-x = 8-4x => 3x = 5 => x=5/3

5/3 is the answer

9 ^( 3-x) =81^( 4-2x) (3^2)^(3-x)=(3^4)^(4-2x) 3^(2*(3-x))=3^( 4*(4-2x)) on camparing 2(3-x) =4(4-2x) 6-2x=16-8x -2x+8x=16-6 6x=10 x=10/6 x=5/3

x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be

If x + 1/x = 1 then x^(1729) + x^(-1729) = ?

If we know x + 1/x =2 then what would be the value of x^2048 + 1/x^2048 +x^2047 - 1 / x^2047 + 1/x^2049 - x^2049 +2

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