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9^(3-x) = 81^(4-2x)
=> 9^(3-x) = 9^(8-4x)
=> 3-x = 8-4x
=> 3x = 5
5/3 is the answer
9 ^( 3-x) =81^( 4-2x)
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
x + 1/x = 1
x^(1729) + x^(-1729) = ?
If we know
x + 1/x =2
then what would be the value of
x^2048 + 1/x^2048 +x^2047 - 1 / x^2047 + 1/x^2049 - x^2049 +2
Note: Read carefully...
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