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Given positive real numbers x, y, and z that satisfy the following system of equations:
x² + xy + y² = 9,
y² + yz + z² = 4,
z² + zx + x² = 1,
Find x + y + z
But I calculated the first equation and that equaled 9.
How many integer solutions are there to the system of equations below and which are those solutions?
x^2+y-z = 42
x+y^2-z = 18
x, y, z are 3 non zero positive integers such that x+y+z = 8 and xy+yz+zx = 20,
What would be minimum possible value of x*y^2*z^2
Find the number of ordered pairs (x,y) satisfying the system of equations -
x + y^2 = 12
x^2 + y = 12
If a and b are real numbers that satisfy the equation below, what is the value of a and b respectively?
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