IF 1234=201006, 9155=392016, 4282=401604, 2346=421513, Then 4356=?

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posted Apr 11, 2014

1 Solution

4356 = 571819

split answer into 3 blocks of two Like ( 57 ) ( 18 ) ( 19 )

57 = ( 4 x 3 ) + ( 3 x 5 ) + ( 5 x 6 )
18 = ( 4 + 3 + 5 + 6 )
19 =

Sorry sterday in half sleep i did a mistake.. unable to find last two digits.. will post that soon..

1234 = 201006

20 = ( 1 x 2 ) + ( 2 x 3 ) + ( 3 x 4 )
10 = ( 1 + 2 + 3 + 4 )
06 =

solution Apr 16, 2014 by anonymous
What is the logic????
last two digits????

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–1 vote

If;

1 + 9 + 11 = 1
&

12 + 11 + 9 = 1

Then;

14 + 11 + 9 = ?

If

8638 + 7542 = 1215

&

5589 + 2468 = 4331

Then;

1357 + 1919 = ????

+1 vote

3 rational numbers form a geometric progression in its current order.

1. If 8 is added to the middle number, then this new sequence forms an arithmetic progression.
2. If 64 is later added to the last number, then this yet another sequence forms a geometric progression again.
3. First number of these sequences is an integer.

Find the numbers?