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Answer is 130

(1*1*1)+1 = 02 (2*2*2)+2 = 10 (3*3*3)+3 = 30 (4*4*4)+4 = 68 (5*5*5)+5 = 130

If 1= 02, 2=10, 3=30, 4=68 THEN 5= ?

ANSWER = 130

1*2=2 2*5=10(the 2+3=5) 3*10=30(5+5=10) 4*17=68(10+7=17) 5*26=130(17+9=26).odd or prime numbers...

the answer is 130.

for e.g. 4=68 how is it will show 4*4*4+4=68

same way 5*5*5+5=130, i.e. 5*5*5=125, and 125+5=130

Just an alternative method..

1*2=2

2*5=10.......(5-2=3)

3*10=30........(10-5=5)

4*17=68........(17-10=7)

5*x=?.......(x-17=9)

Therefore x=26

5*26=130

(1^3)+1=2 (2^3)+2=10 (3^3)+3=30 (4^3)+4=68 (5^3)+5=130

Really good question Ans is: 130 Explanation: 1*2=02 2*5=10 3*10=30 4*7=68 5*26=130 because, its 1*1+1=2 2*2+1=5 3*3+1=10 .... 5*5=26.....................so easy

1=02=1*2=0+2(prime)

2+3(prime)=5 2=10=2*5

5+5(prime)=10 3=30=3*10

10+7(prime)=17 4=68=4*17

Similarly, 17+11(prime)=28 (2,3,5,7,11,13-prime numbers) Therefore, 5*28=140...

here we have, 1^3+1=2 2^3+2=10 3^3+3=30 4^3+4=64 So, 5^3+5=130 i.e, 5 = 130.

130 n(n*n +1)