# 7 multiple of a two digit number is a perfect square. What will be the Sum of all such possible two digit numbers?

+1 vote
94 views
posted Mar 29, 2015

## 2 Solutions

It would be 91
As 14^2=196 so two digit will be 28 *7
As 21^2=441 so two digit will be 63*7
So sum of digits=28+63=91

solution Mar 29, 2015
+1 vote

1st) 7 * 28 = 196 = 14*14
2nd) 7*63 = 441 = 21*21

28+63=91

solution Mar 30, 2015

Similar Puzzles

The sum of 3 single digit numbers is 15 less than their product . If we subtract 2 from first given number then sum of these numbers will become 7 more than their product. Then what will be the product of given 3 numbers?

A five digit number has all non-zero different digits & decreasing arranged. Average of all the digits of the numbers is 5. The difference of number and the number formed by reversing the order of digits is 84942.

What would be the sum of all such possible digits -
1) 196052
2) 196002
3) 195984
4) 195842
5) 195802
6) 195798
7) 195602
8) 195588
9) 195512
10)195490