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Taking AB= 6
Solving for white region
Pie*(6^2) - pie*(3^2)
For blue region
Pie*(9^2) - 27*pie
We get ratio as 2:1
let the full diameter be d
then white area on both sides=(pi/4)*(2*d/3)^2-(pi/4)*(d/3)^2 = (pi/4)*d^2*(1/3)
since blue area is whole area-white area it is =(pi/4)*d^2*-(pi/4)*d^2*(1/3) = (pi/4)*d^2*(2/3)
thus blue area: white area = (2/3)/(1/3) or 2:1 ans
If ABCD is a square of area 1. E, F are mid points of AB and BC respectively. What is the area of blue region?
In a circle of radius 1, an equilateral triangle is inscribed in the circle as shown. What is the area of the blue region?
In the figure, if ABCD and EFGC are squares with areas R and S respectively. What is the area of the blue region?
A square is inscribed in a circle and a circle is inscribed in that square. What will be the ratio of the area of the bigger circle to that of the smaller circle?
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