What is the India’s rank in the 2017 Digital Evolution Index (DEI)?

In LTE RRC connected state.what all protocols stack & signaling used to access internet in uplink direction at Enodeb?

Downlink Data rate is more than Uplink data rate

India’s first museum on the Partition of the Indian Sub-continent will open in which state?

Who has won the 2017 Kalpana Chawla Award for courage and daring enterprise?

Who has authored the book “The Adivasi Will Not Dance”?

What is the relative role of the Reserve Bank of India and the government in currency management?

What is the highest currency and coin that can be issued in India?

Who is the first crowned Czar (Tsar) of Russia?

What is the name of the debut film of Ashutosh Gowarikar as a director?

Taking AB= 6 BC=6 CD=6 Solving for white region Pie*(6^2) - pie*(3^2) =27*pie For blue region Pie*(9^2) - 27*pie =54*pie

By solving We get ratio as 2:1

let the full diameter be d then white area on both sides=(pi/4)*(2*d/3)^2-(pi/4)*(d/3)^2 = (pi/4)*d^2*(1/3) since blue area is whole area-white area it is =(pi/4)*d^2*-(pi/4)*d^2*(1/3) = (pi/4)*d^2*(2/3) thus blue area: white area = (2/3)/(1/3) or 2:1 ans

If ABCD is a square of area 1. E, F are mid points of AB and BC respectively. What is the area of blue region?

In a circle of radius 1, an equilateral triangle is inscribed in the circle as shown. What is the area of the blue region?

In the figure, if ABCD and EFGC are squares with areas R and S respectively. What is the area of the blue region?

A square is inscribed in a circle and a circle is inscribed in that square. What will be the ratio of the area of the bigger circle to that of the smaller circle?