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Find 28383rd term of the series :: 12345678910111213141516171819202122..... ?

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posted May 19, 2015 by Ankit Kamboj

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1 Solution

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12345678910111213141516171819202122..... we have

9 digits in 0 to 9

90*2= 180 digits in 10 to 99

900*3= 2700 digits in 100 to 999

so till here we have 9+180+2700= 2889 digits

remaining digits 28383-2889 = 25494
here we have 4 digits number so

25494/4  == 6373 + 2 

1000 ==== 1st
1001 ==== 2nd {{{ 2nd + 999 }}}

7373 ======6374th {{{ 6374 + 999}}}

hence 2nd digit of 6374th number , ie 7373 , is 3

so 3 is the answer

solution May 21, 2015 by Ankit Kamboj
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