top button
Flag Notify
    Connect to us
      Facebook Login
      Site Registration Why to Join

    Get Free Puzzle Updates

Facebook Login
Site Registration

If x = 29y+7 and x-y is divisible by 5, then what is the possible value of y where x and y both are integers?

–3 votes
135 views
posted May 29, 2015 by Atif

Share this puzzle
Facebook Share Button Twitter Share Button Google+ Share Button LinkedIn Share Button Multiple Social Share Button

2 Solutions

0 votes

One.
x=36 (36=29+7 and
36-1=35 which
divided by 5=7)

solution Nov 14, 2015 by anonymous
0 votes

we have,
x-y is divisible by 5
say, x-y=5*k
where k be any integer.
x=5k+y................................................(i)
also we have
x = 29y+7
5k+y=29y+7 .............................from (i)
or, 28y=5k-7
or, y=(5k-7)/28............................(ii)

from (ii), it is clear that y will be integer only when (5k-7) is completely divisible by 28.
one of the possible cases is when k=7, then y=(35-7)/28=28/28=1
so, there are infinite number of possible integer values of y.

hence , y=1 is one of the possible values of y.

solution Mar 11, 2016 by Ashutosh Kumar Anand
Contact Us
+91 9880187415
sales@queryhome.net
support@queryhome.net
#470/147, 3rd Floor, 5th Main,
HSR Layout Sector 7,
Bangalore - 560102,
Karnataka INDIA.
QUERY HOME
...