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If a bamboo 32 meters high is broken by wind so that the tip meets the ground at a point 16 meters far from the base, at what height above the ground was it broken?
Using Pythagoras gives us bc^2 + 16^2 = ac^2.
bc + ac = 32, therefore bc^2 + 16^2 = (32-bc)^2 = 1024 - 64*bc + bc^2
=> 768 = 64* bc => bc = 12
Ans is 12
Let height above ground be X
So, X^2+16^2 =(32-X)^2
By solving we get X=12
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