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abcde=1 (where a,b,c,d and e are all positive real numbers)
what is the minimum value of a+b+c+d+e?
using A.M > = G.M
(a+b+c+d+e) / 5 >= [abcde]^(1/5)
== a+b+c+d+e >= 5
thus a+b+c+d+e=0 maximum
a + b + c = 8
a.b.c = 27
Is there exist solution/s in (a,b,c) where a, b and c are positive real numbers?
Find the value of a+b+c+d
If a,b,c,d are positive numbers of algebraic sequence and
a,b,c+4,d+13 are positive numbers of a geometric sequence
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