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ABC has a right angle at B with AC=60, AE=52 and CD=39. Find the length of DE?
AB.sq + BC.sq = 3600
AB.sq + BE.sq = 52.sq (2704)
BD.sq + BC.sq = 39.sq (1521)
AB.sq + BE.sq + BD.sq + BC.sq = 2704 + 1521= 4225
BE.sq + BD.sq = 4225 - 3600 = 625
√625 = 25 (ans)
In the following diagram if AB=BC and CD=DE, find the value of Angle GCF?
The figure shows an isosceles triangle with AB = BC. The line DE cuts AC extended at F. If AD=5, CE=3 and EF=8 find DE.
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