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If P=Sin A.Sin B, Q= Sin C.Cos A, R = Sin A.Cos B and S=Cos A.Cos C then 5(P^2+Q^2+R^2+S^2) = ??

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If
P=Sin A.Sin B,
Q= Sin C.Cos A,
R = Sin A.Cos B and
S=Cos A.Cos C
then
5(P^2+Q^2+R^2+S^2) = ??

posted Jul 21, 2015 by anonymous

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1 Solution

+2 votes
 
Best answer

We can see that

 P^2 + R^2 =  {sin(A)}^2     and  Q^2 + S^2 = {Cos(A)}^2

adding we get P^2 + R^2 + Q^2 + S^2 = 1

So
5(P^2 + R^2 + Q^2 + S^2) = 5

solution Jul 23, 2015 by Ankit Kamboj
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