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If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days.
What will be the time taken by 15 men and 20 boys in doing the same type of work?
Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y
6x + 8 y = 1/10
26x + 48y = 1/2
Solving we get,
x = 1/100 and y = 1/200
(15 men + 20 boy)'s 1 day's work = 15/100 + 20/200 = 1/4
15 men and 20 boys can do the work in 4 days
If 9 boy working 15/2 hours a day can finish a work in 20 days, then how many days will be taken by 12 boy working 6 hours a day to finish the work, it being given than 3 boy of latter type work as much as 2 boy of he former type in the same.
8 woman and 12 men complete a certain piece of work in 9 days. Each woman takes twice the time taken by a man to finish the work. In how many days will 12 men finish the same work
If A men working A hours a day can do A units of a work in A days, then how many units of work can be completed by B men working B hours per day.
A contractor took a job for his group to do in 20 days. But 12 men did not come up for the job and job was done by remaining man in 32 days. What was the original size of the contractor’s team?
3 men and 8 women complete a task in same time as 6 men and 2 women do.
How much fraction of work will be finished in same time if 4 men and 5 women will do that task?
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