P can do a work in 19 days. Q can do the same work in 9.5 days and R can do the same in 28.5 days. Q and R start the work and leave after 3 days. P finishes the remaining work in X days. What is the value of X?
Short answer: 11 days. Long answer: P's speed = 1 work / 19 days Q's speed = 1 work / 9.5 days R's speed = 1 work / 28.5 days Since Speed × time = work [((1/9.5)+(1/28.5))×3 + (1/19)×X] = 1 X = 11 Days.
11 days
If W is work then W=19P=9.5Q=28.5R
Daily speed is: P=W/19 Q=W/9.5 R=W/28.5
W=3*(W/9.5+W/28.5)+X*W/19 X=11
P can do a work in 20 days. Q can do the same work in 12 days and R can do the same in 16 days. Q and R start the work and leave after 6 days. P finishes the remaining work in X days. What is the value of X?
P can do a work in 12 days. Q can do the same work in 8 days and R can do the same in 6 days. Q and R start the work and leave after 2 days. P finishes the remaining work in X days. What is the value of 1.1X?
P is able to do a piece of work in 15 days and Q can do the same work in 10 days. If they can work together for 2 days, what is the fraction of work left?
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
Rahul and Maneesh working separately can do a piece of work in 9 days and 12 days respectively. If they work for a day alternately, Rahul beginning, in how many days, the work will be completed?
