In a Right angle triangle ABC - AB=3,AC=4 & BC=5. At BC, E is middle point and D is altitude AD. Find distance DE=?

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In a Right angle triangle ABC

AB=3,AC=4 & BC=5

at BC,E is middle point and D is altitude AD

Find distance DE=?

it is not a difficult question everyone who know maths ...
Can YOU solve it easily ...... solve it in one line...........or in second..........?

posted Sep 20, 2017 by Mayank
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1 Answer

Point D is the foot of the altitude from the right angle, so CA must be the geometric mean of CD and CB.

(CB)(CD) = CA²
5(CD) = 4²
CD = 16/5

Point E is the midpoint of CB, so CE must be half of CB.

CE = CB/2
CB = 5/2

DE
= CD - CE
= 16/5 - 5/2
= 32/10 - 25/10
= 7/10

answer Dec 31, 2017 by Yasin Hossain Siinan

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