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Product of three consecutive numbers are 7980. Then the sum of these consecutive numbers would be?

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Product of three consecutive numbers are 7980. Then the sum of these consecutive numbers would be?
posted Jan 29, 2018 by Brijesh Talwar

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1 Answer

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a×(a + 1)×(a + 2) = 7980
a×(a^2 + 3a + 2)
a^3 + 3a^2 + 2a - 7980 = 0
a = 19 therefore b = 20 and c = 21
And a + b + c = 60.

answer Jan 29, 2018 by Tejas Naik
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