# Find next number in the series... 1/1...3/2 ...7/5...17/12...41/29...?

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posted Sep 3, 2014

## 4 Solutions

``````Ans : 99/70
``````

Solution:

``````next_num = (numerator + 2 * denominator) / (numerator + denominator)

(1 + 2 * 1)   / (1 + 1)   = 3/2
(3 + 2 * 2)   / (3 + 2)   = 7/5
(7 + 2 * 5)   / (7 + 5)   = 17/12
(17 + 2 * 12) / (17 + 12) = 41/29
(41 + 2 * 29) / (41 + 29) = 99/70
``````
solution Sep 3, 2014
+1 vote

next_num = (numerator + denominator + denominator) / (numerator + denominator)
(1+1+1) / (1+1) = 3/2
(3+2+2) / (3+2) = 7/5
(7+5+5) / (7+5) = 17/12
(17 +12+ 12) / (17+12) = 41/29
(41+29+29) / (41+29) = 99/70

solution Sep 3, 2014 by anonymous
+1 vote

Ans 99/70
As 1/1 , 3/2 = 2+1/1+1, 7/5= 5+2/3+2 ,
17/12= 12+5/7+5, 41/29=29+12/12+17,
So 70+29/41+29= 99/70

solution Dec 14, 2014

numerator of next term=2*numerator of previous term + numerator of second previous term;
denominator of next term=numerator of previous term + denominator of previous term.
ans=99/70

solution Mar 16, 2016

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