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28 . twice of 28 is 56 and difference from 14 is 42 and same difference from 28 is 14
Husband + wife = 91 years
Husband + X = ( Wife + X ) * 2
42 + X = ( 14 + 2) * 2
X = 14 years passed
Therefore She is 14 + 14 = 28 years old
A husband and wife have a combined age of 91. If husband is now twice as old as his wife was when he was as old as she is now.
How old are they now?
Six years ago a woman was nine times the age of her niece and she is now three times the age of her niece.
What are their current ages?
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