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On equating the above equation , we get
x (x^2+6x+18)(x+6) = 159919
(x+3-3)(x^2+6x+18)(x+3+3) = 159919
[(x+3)^2 - 9] [(x+3)^2 + 9] = 159919
(x+3)^4 - 81 = 159919
(x+3)^4 = 160000
x+3 = 20
x = 17
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
If we know
x + 1/x =2
then what would be the value of
x^2048 + 1/x^2048 +x^2047 - 1 / x^2047 + 1/x^2049 - x^2049 +2
Note: Read carefully...
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