What is the probability that picked ball is neither red nor green?

Question

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

Answer 1

total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green = event that the ball drawn is blue.
So n(E) = 7

P(E) = n(E)/n(S) =7/21

or P(E) = 1/3

Answer 2

7/(8+7+6) = 1/3