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7 multiple of a two digit number is a perfect square. What will be the Sum of all such possible two digit numbers?

+1 vote
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posted Mar 29, 2015 by Salil Agrawal

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2 Solutions

+3 votes

It would be 91
As 14^2=196 so two digit will be 28 *7
As 21^2=441 so two digit will be 63*7
So sum of digits=28+63=91

solution Mar 29, 2015 by Jaspalsingh Parmar
+1 vote

1st) 7 * 28 = 196 = 14*14
2nd) 7*63 = 441 = 21*21

28+63=91

Answer is 91

solution Mar 30, 2015 by Chirag Gangdev



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