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It would be 91
As 14^2=196 so two digit will be 28 *7
As 21^2=441 so two digit will be 63*7
So sum of digits=28+63=91
1st) 7 * 28 = 196 = 14*14
2nd) 7*63 = 441 = 21*21
Answer is 91
The sum of 3 single digit numbers is 15 less than their product . If we subtract 2 from first given number then sum of these numbers will become 7 more than their product. Then what will be the product of given 3 numbers?
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