# A 120 digit number is formed like ::123456789101112131415.... Find remainder when this number is divided by 8 ?

+1 vote
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posted May 19, 2015

## 1 Solution

Number will be something like
123456....616263646

(a+b)mod n = a mod n + b mod n so
(123...616263000+646) mod 8 = 123...616263 mod 8 + 646 mod 8
1000 or any multiple of it remainder is zero so
= 0 + 646 mod 8
= 0 + 6

Hence
remainder is six

solution May 19, 2015
Dear Sir, the number would be like 1234..... , it has 120 terms , probably i think it may not go till 120 , i still have doubt .
Oh my bad I will correct it and will update u :)
Now it is perfectly fine :)

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when divided by 10 leaves a remainder 9 and
when divided by 9 leaves a remainder 8,
when divided by 8 then leaves a remainder 7,
and similarly till 1 ?

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