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How many integer values of x and y are there such that 4x + 7y= 3 , while |x|<500 and |y|<500 ?

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posted May 19, 2015 by Ankit Kamboj

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1 Solution

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possible solution of 4x + 7y = 3 -500<= x <= 500 , -500 <=y <= 500

are x=6 , y= -3
x=13 , y=-7

   x=-1 , y= 1

 x= -8   y=5

so x has a gap of 7 units 497/7 = 71 ,, so last term is - 498 ,, ,,,,,,,,,, - 1 , 6 , 13 ,,,,,,,, 496

so we get 143 terms , so our answer is 143

solution May 21, 2015 by Ankit Kamboj



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