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What is the reminder when 2^123456789 is divided by 7?

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posted May 20, 2015 by Harshita Dhaliwal

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2 Solutions

+1 vote

since
41152263*3=123456789 and (2^3) / 7 = 1 (remainder) , hence we have the remainder as 1

solution May 21, 2015 by Ankit Kamboj
+1 vote

Ans is 1.
2^129456789 can be written as (2^3)^43152263.
= (7+1)^43152263
By expanding the above expression...we get the result as 7*k + 1^43152263.
So the remainder is 1.

solution Jun 5, 2015 by Sreenu569
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