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9 men do work in 10 days=10*9=90 unit
work left=180 unit
work to be done in one day=180/2=90 unit
90 men are required per day
10 * 3 = 30 days;
30 - 10 = 20 days it would take to do the job of nine men.
9 * 20 = 180 man-days;
180/2 = 90 men;
90 - 9 = 81 men additional men required to finish the remaining work in 2 more days.
Six men do a piece of work in 10 days with an effort of 6 hours per day. How many extra men are required for doing the work of double strength in 4 days with an effort of 5 hours per day
If 9 boy working 15/2 hours a day can finish a work in 20 days, then how many days will be taken by 12 boy working 6 hours a day to finish the work, it being given than 3 boy of latter type work as much as 2 boy of he former type in the same.
If 15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take, if 3 women do as much work as 2 men?
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