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If abcde=1; and a,b,c,d and e are all positive real numbers then what is the minimum value of a+b+c+d+e?

+1 vote
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If
abcde=1 (where a,b,c,d and e are all positive real numbers)
then
what is the minimum value of a+b+c+d+e?

posted Jun 7, 2015 by anonymous

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2 Solutions

+5 votes

using A.M > = G.M

(a+b+c+d+e) / 5 >= [abcde]^(1/5)

== a+b+c+d+e >= 5

solution Jun 8, 2015 by Ankit Kamboj
–1 vote

1x1x1x1x1=1
1+-1+1+-1+1+-1=0
thus a+b+c+d+e=0 maximum

minimum=-1

solution Aug 12, 2016 by Ben Gichuhi
a,b,c,d,e are positive real number..so it can't be -1.
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