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If in the following image AC is the diameter of the circle where AB = 4cm and BC = 1cm. Find the x?
Let AD=y and DC=z , in triangle ADC 25=y^2 + z^2
in triangle ADB y^2=x^2 + 16
in triangle BDC z^2=x^2 +1
solving we get 25=2x^2 + 17
Ans: 2 cm
From the center of the circle, draw a radius (len = 2.5cm) to point D. Now you get a right angled triangle with the sides : x cm, 1.5 cm and 2.5 cm. Using Pythogoras, you get x^2 = 2.5^2 - 1.5^2 which gives x = 2 cm.
i have seen the other two answers. therefore another simple solution is as under:
if we complete the circle and draw mirror of x, applying one theorem of geometry x*x=4*1 or x=2
X is the geometric mean of 4 and 1.
This is the square root of 4x1.
X therefore is 2.
Let us consider that the centre of the circle lies between A and Let it be O
Then join O and D
In the triangle DOB
Therefore applying Pythagoras theorem
Solving we get x= 2cm
In triangleABC, side AB = 20, AC = 11, and BC = 13. Find the diameter of the semicircle inscribed in ABC, whose diameter lies on AB, and that is tangent to AC and BC.
If lengths of sides AB, BC and AC of a right angle triangle are in a geometric progression, what is the ratio between AC and AB?
The figure shows an isosceles triangle with AB = BC. The line DE cuts AC extended at F. If AD=5, CE=3 and EF=8 find DE.
In a Right angle triangle ABC
AB=3,AC=4 & BC=5
at BC,E is middle point and D is altitude AD
Find distance DE=?
it is not a difficult question everyone who know maths ...
Can YOU solve it easily ...... solve it in one line...........or in second..........?
In the following diagram if AB=BC and CD=DE, find the value of Angle GCF?
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