Who is the first women boxer to be honoured with the Rajiv Gandhi Khel Ratna Award?

Which is the only Test playing nation that India has never beaten in T20 International ?

The Doctrine of Lapse was one of the causes for which rebellion ?

Where did Sunita Williams display the Indian flag on Independence day in 2012 ?

Which of these can be estimated from the colour of the nose of a lion?

At Rio 2016, who made the record for the fastest goal scored in football in Olympics by scoring a goal in 14 seconds?

Which of these Indian supreme court judges also served in the International Court of Justice?

Which of the following tools is part of the name of an Olympic sporting events ?

Which of these Indian Para-athletes won the gold medal in high jump at the Rio Paralympic Games ?

Which of these companies is a major manufacturer of high speed passenger trains?

If x, (x^3+1) and x^4 are in arithmetic progression,then what will be possible sum of 3 terms of arithmetic progression? ( given that x is real number )

Since the terms are in A.P

we have 2*(x^3 + 1) = x + x^4;; solving we get ;; (x-2)*(x+1) = 0

so we get values of x= 2 or -1 Hence possible sums of three terms will be

for x=2 will be { 2+9+16 ) = 27 for x= -1 will be {-1 + 0 + 1 } = 0

1) 1/2 2) 1 3) 3/2 4) 2 5) 5/2 6) 5/3 7) 5/4 8) 7/6 9) 6/13 10) 3/16

First and last term of a geometric progression are 3 and 96. If the sum of all these terms is 189, then find the number of terms in this progression.

An integer x is selected in such a way that

x + x^(1/2) + x^(1/4) = 276

Then what would be the sum of all digits of the number y where

y = 100000 x^(1/4) + 1000 x^(1/2) + x

x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be