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A four digit number is such that the product of all of its digits is 126. The sum of all the digits is equal to the 2 digit number formed by using thousands digit and tens digit (Thousand digit in tens place & ten digit in units place) which in turn is equal to 19.
Then find out the difference of units and thousand place numbers (given that this difference is positive)
A four digit number having all digit successive when substracted by the number formed by using all the digits in reverse pattern (ie reverse of xyz is zyx) gives a four digit number. The sum of all digits of that number is 18.
What will be the product of thousand and units digit of that number ?
Given positive real numbers x, y, and z that satisfy the following system of equations:
x² + xy + y² = 9,
y² + yz + z² = 4,
z² + zx + x² = 1,
Find x + y + z
2 two digit numbers chosen in such a way that all 4 digits used are distinct, are such that their sum is 90.
How many such pairs are possible if in both numbers units place is 1 more than tens place?
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