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In a billiard table shaped like a right isosceles triangle as in the diagram, a ball struck at marked vertex...

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It is well known that, in a billiard table shaped like a right isosceles triangle as in the diagram below, a ball struck at the marked vertex cannot return to that same point after any number of reflections. The ball may bounce any number of times, and if the ball hits a vertex point as opposed to a side, then the reflections are absorbed.

Does this also hold true for non-right isosceles triangles?

billiard table

posted Jan 18, 2018 by anonymous

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1 Answer

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The answer is No. This can easily be seen by considering an equilateral triangle and striking the ball straight off the opposite side.

answer Feb 3, 2018 by Yasin Hossain Siinan



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